(3x+2)(x+2)=3x^2

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Solution for (3x+2)(x+2)=3x^2 equation: 



(3x+2)(x+2)=3x^2

We move all terms to the left:

(3x+2)(x+2)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+(3x+2)(x+2)=0

We multiply parentheses ..

-3x^2+(+3x^2+6x+2x+4)=0

We get rid of parentheses

-3x^2+3x^2+6x+2x+4=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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